((x-4)/((x^2)-9))*((2x+6)/(3x-12))

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Solution for ((x-4)/((x^2)-9))*((2x+6)/(3x-12)) equation: 


D( x )

x^2-9 = 0

3*x-12 = 0

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

3*x-12 = 0

3*x-12 = 0

3*x-12 = 0 // + 12

3*x = 12 // : 3

x = 12/3

x = 4

x in (-oo:-3) U (-3:3) U (3:4) U (4:+oo)

((x-4)/(x^2-9))*((2*x+6)/(3*x-12)) = 0

((x-4)*(2*x+6))/((x^2-9)*(3*x-12)) = 0

( 2*x+6 )

2*x+6 = 0 // - 6

2*x = -6 // : 2

x = -6/2

x = -3

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -3} 

x in { 4} 

x belongs to the empty set

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